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Last modified: December 9, 2021 ✓

Avogadro's Number ----------------- One Mol is the number of atoms in 12 g of Carbon-12. This number is called Avogadro's Number, NA and is equal to: 6.022 x 1023 Atomic Mass Unit(amu) --------------------- One amu (u) is defined as 1/12 of the mass of an unbound neutral atom of Carbon-12 in its nuclear and electronic ground state. u = 1.660538921(73)×10-24 grams Note: u is simply the inverse of Avogadro's number expressed in grams. = 1/(6.022 x 1023) grams Molar Mass ---------- The molar mass of any molecular is the sum of the atomic masses of the atoms in the molecules. Atomic Weight ------------- The atomic weight of an element is the weighted average of the atomic masses of the different isotopes of an element. Formulas -------- # of Mols = Mass (g)/Molar Mass (g/M) # of molecules/atoms = # of Mols x 6.022 x 1023 Examples -------- 1. What is the molar mass of Carbon Tetrachloride, CF4? MM of C = 12 MM of F = 19 12 + 4(19) = 88 g/mol 2. Which is the formula for the compound whose percent composition 47.51% O, 38.62% K and 13.87% N? # of Mols = Mass/Molar Mass MM of O = 16 MM of K = 39 MM of N = 14 O: 47.51/16 = 2.97 Mols K: 38.62/39 = 0.93 Mols N: 13.87/14 = 0.99 Mols Compute the ratios: N: 0.99/0.99 = 1 K: 0.93/0.99 ~ 1 O: 2.97/0.99 ~ 3 Therefore, K2NO2 3. What is the formula for a compound that contains 64.75g Nitrogen and 185.25g Oxygen? # of Mols = Mass/Molar Mass 64.75/14 = 4.6 Mols of Nitrogen 185.25/16 = 11.575 Mols of Oxygen The ratio 11.575/4.6 ~ 2.5 (= 5/2) Therefore, N2O5 is the correct formula. 4. What is the mass of 8 moles of Sodium Chloride? Mass = # of Mols x Molar Mass = 8 x 58.44 = 467.52g 5. How many moles of atoms are in one mole of AlPO4? Mols of P = 1 Mol2 of O = 4 Mols of Al = 1 --- 6 5. How many molecules are in 3.6 grams of NaCl? # of molecules = Mass/Molar Mass = 3.6/58.44 = 0.062 Mols # of molecules = Mols x 6.022 x 1023 = 3.7 x 1022 molecules 6. How many grams are in 1.946 moles of NaCl? Mass = Mols x Molar Mass = 1.946 x 58.44 = 113.8g 7. What is the percent composition of Phosphorus in Zn3(PO4)2? MM of P = 30.97 MM of O = 16 MM of Zn = 65.38 % = 2(30.97)/[3(65.38) + 2(30.97 + 4(16))] x 100 = [61.94/(197.44 + 189.94) = 61.94/387.38] x 100 = 16% 8. Calculate the number of molecules in 4.0 Mols of H2O. # of molecules = # of Mols x 6.022 x 1023 = 4 x 6.022 x 1023 = 24.088 x 1023 molecules 9. What is the mass in grams of 1.02 x 1024 atoms of Manganese (Mn)? # of Mols = # of atoms/6.022 x 1023 = 1.02 x 1024/6.022 x 1023 = 1.69 Mols Mass = # of Mols x Molar Mass = 1.69 x 54.94 = 93g