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Last modified: January 26, 2018

Hypothesis Testing ------------------ Hypothesis t esting asks the question is the sample statistic different to the population parameter. Null hypothesis H0: = Alternate hypothesis H1: ≠ <= 2 tailed < <= 1 tailed > <= 1 tailed So what are the 4 possible outcomes? 1. Correctly accept H0 and reject H1 2. Correctly accept H1 and reject H0 3. Accept H1 when H0 is true - TYPE 1 error = α Where α is the SIGNIFICANCE LEVEL of the test. 4. Accept H0 when H1 is true - TYPE 2 error = β Where 1 - β is the POWER of the test. p-value ------- The p-value for any hypothesis test is the α level at which we would be indifferent between accepting or rejecting H0. That is, the p-value is the α level at which the given value of the sample statistic is on the borderline between the acceptance and rejection regions. The p-value corresponds to the shaded areas. The 1-tailed test is twice the 2-tailed value. Consider a Z-distribution and α = 0.05: 1-tailed: p = 0.05 for a critical value of Z = -1.645 or +1.645 Therefore, if the computed Z score was < -1.645 we would reject    _ H0 and accept H1: x < μ If the computed Z score was < +1.645 we would reject    _ H0 and accept H1: x > μ 2-tailed: p = 0.025 for a critical value of Z = -1.96 or +1.96 Therefore, if the computed Z score was < -1.96 or > +1.96 we    _ would reject H0 and accept H1: x ≠ μ The χ2 and F distributions are not symmetric and so the left and right tails are different. The p-value can also be thought of as the probability of obtaining a test statistic as extreme as or more extreme than the actual test statistic obtained, given that H0 is true. The null hypothesis is rejected if the p-value is less than or equal to α (i.e. the test statistic falls with in the shaded areas). In the language of statistics we say: "At the α level of significance we can accept/reject H0, there is not/is a difference (≠, < or >) between the sample and the population". F Test example: Suppose you randomly select 7 marbles from company As production line and 12 marbles from company Bs production line and measure their diameters. Assume you are given: sA = 1.0 and sB = 1.1 F = sA2/sB2 = 1/1.21 = 0.83 H0: σA = σB H1: σA ≠ σB From tables F0.05 for v1 = n1 - 1 = 6 and v2 = n2 - 1 = 11 is equal to 3.0946. Since 0.83 < 3.0946 the result is not significant and there is no reason to reject H0.